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The last quarter of the jouney menas 1/4th of the total time it requires in its total journey.Let total time be 4t, u = 0. So, v at 3t = 3gt, and at 4t = 4gt. by v² = u² + 2as, 16g²t² = 9g²t² + 2g(81) 7g²t² = 162g 7gt2 = 162 t² = 162 / 7g t = 1.5 sec. but time is 4t = 6 sec. So velocity on reaching = 4gt = 58.8 m/s With this velocity, height of fall = 2t(58.8) = 705.6mRegards,Nirmal SinghAskiitians Faculty
The last quarter of the jouney menas 1/4th of the total time it requires in its total journey.
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