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a. A laser beam is aimed 15.95° above the horizontal at a mirror 11,648 m away. It glances off the mirror and continues for an additional 8570. m at 11.44° above the horizon until it hits its target. What is the resultant displacement of the beam to the target? b. 2) Three forces act on a point: 3 N at 0°, 4 N at 90°, and 5 N at 217°. What is the net force?

billy , 8 Years ago
Grade 12th pass
anser 1 Answers
Arun
Dear student
 
11648 cos(15.95) = 11199.57 
11648 sin(15.95)= 3200.85 
(11199.57 i , 3200.85 j) 

8570 cos(11.44) = 8399.73 
8570 sin(11.44) = 1699.78 
(8399.73 i , 1699.78 j) 

R= (11199.57 + 8399.73)i + (3200.85+1699.78)j 
R= (19599.3)i + (4900.63)j
 
 
Regards
Arun (askIITians forum expert)
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