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A 5kg steel ball traveling horizontally strikes a massive wall at 15m/s and rebounds elastically, returning horizontally back on its original path at 7m/s. If it is in contact with the wall for 0.20 seconds, what is the average force exerted by the wall on the ball?

jlm , 7 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear student
 
FΔt = mΔv 
F * 0.20s = 5kg * (15 - -7)m/s 
avg F = 550 N 
 
Regards
Arun (askIITians forum expert)

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