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A 2 kg block slides on a horizontal floor with a speed of 4m/s. It strikes a uncompressed spring, and compresses it till the block is motionless. The kinetic friction force is 15N and spring constant is 10,000 N/m. The spring compresses ?

A 2 kg block slides on a horizontal floor with a speed of 4m/s. It strikes a uncompressed spring, and compresses it till the block is motionless. The kinetic friction force is 15N and spring constant is 10,000 N/m. The spring compresses ?

Grade:12

2 Answers

Piyush
18 Points
7 years ago
As the block is moving with some initial velocity it must be having must KE. Finally it comes to rest so kinetic energy final will be zero.. it ll have some potential energy. As frictional force is also given it will some work done by friction.. applyling the work energy theorm... Work done(external force) + work done (non conservative force ) = change in kinkinetic energy+ change in potential energy. 0 + 15x = kf - ki + pf - pi. 0 + 15x = 0 + 1/2mv2 + k/2x² - 0. On putting the values you get a qquadric equation ie 5000x² - 15x -16=0 solving this equation x = 0.056m or 5.6 cm (approximately) hope it helps!! Cheers!!!
ankit singh
askIITians Faculty 614 Points
3 years ago

Change in kinetic energy=work done by the force

0.5mv2=0.5kx2
x=v×km​​
x=4×104m2​​
=5.657cm.
thank u regards ankit singh maniut bhopal

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