Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        a 100g mass particle falls 490 cm downwards from rest position and comes to rest after moving 70 cm down in the sand . calculate the acceleration imposed by the sand on the particle.`
one year ago

20 Points
```							u=0,v=?   s=490cm=4.9m. v^2-u^2=2as from this we get v=9.8 .take it as u in the second case .then v=0 s=70cm=0.7m again use the third kinematic equation.then we get answer a=-6.86m/s^2.
```
one year ago
20 Points
```							u=0,v=? s=490cm=4.9m. v^2-u^2=2as from this we get v=9.8 .take it as u in the second case .then v=0 s=70cm=0.7m again use the third kinematic equation.then we get answer a=-6.86m/s^2.
```
one year ago
Think You Can Provide A Better Answer ?

## Other Related Questions on General Physics

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions