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`        A 1.0 H.P. motor pumps out water from a well of depth 20m and fills a water tank of volume 2238 liters at a height of 10 m from the ground. The running time of the motor to fill the empty water tank is (g = 10ms)?`
3 years ago

Vikas TU
10402 Points
```							Mass of water from well => density x volume => 1*2238 gms or 2.238 Kg.Work  = mgh => 2.238*10*20 => 447.6 J For height 10 m from the ground= >  2.238*10*10 => 223.8 JNet Energy required = > 447.6 – 223.8 => 223.8 J1 HP =746 w = 746 Jtime required => 223.8/746 => 0.3 seconds.
```
3 years ago
jitender
114 Points
```							P=1hp = 746wattd=20m ,h=10m ~> H=10+20= 30mVol=2238ltr{1ltr=1Kg : 1ltr=10^-3m^3...;density=10^3Kg/m^3And mass= vol × density}t=?P=W/tt=W/P = mgh/P = 2238×10×30/746 Dect= 900sect=900/60mint=15 min
```
2 years ago
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