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Grade: 12th pass
        A 1.0 H.P. motor pumps out water from a well of depth 20m and fills a water tank of volume 2238 liters at a height of 10 m from the ground. The running time of the motor to fill the empty water tank is (g = 10ms)?
one year ago

Answers : (2)

Vikas TU
6869 Points
							
Mass of water from well => density x volume => 1*2238 gms or 2.238 Kg.
Work  = mgh => 2.238*10*20 => 447.6 J
 
For height 10 m from the ground= >  2.238*10*10 => 223.8 J
Net Energy required = > 447.6 – 223.8 => 223.8 J
1 HP =746 w = 746 J
time required => 223.8/746 => 0.3 seconds.
one year ago
jitender
114 Points
							P=1hp = 746wattd=20m ,h=10m ~> H=10+20= 30mVol=2238ltr{1ltr=1Kg : 1ltr=10^-3m^3...;density=10^3Kg/m^3And mass= vol × density}t=?P=W/tt=W/P = mgh/P = 2238×10×30/746 Dect= 900sect=900/60mint=15 min
						
8 months ago
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