Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Two trains(both are 400m in lenght) are travelling on two parallel tracks with the same speed 72kmph.train A is ahead of train B. Now train B driver decides to overtake train A and accelarates at 1m/s2
and manages to overtake in 50 sec.Now calculate the initial seperation between the trains before the train B's accelaration?
Dear karthik
let the initial seperation = x
In train A frame of reference .velocity of train A is zero.initia velocity of train B is zero.
to overtake train A ,train A has to cover L+800 distance.
so
S =1/2at2
L+800 =1/2 *1 * (50)2
L=450 m
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best. Regards, Askiitians Experts Badiuddin
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !