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The electron in a hydrogen atom is in the first excited state, when the electron acquires an additional 2.86eV of energy. What is the quantum number n of the state into which the electron moves?
Dear karthik,
En=-(13.6eV) * (z^2 / (nfinal)^2 - (ninitial)^2) En=-2.86 z=1 ninitial=2
then nfinal comes out to be 5
We are all IITians and here to help you in your IIT JEE preparation. All the best. If you like this answer please approve it.... win exciting gifts by answering the questions on Discussion Forum Sagar Singh B.Tech IIT Delhi
We are all IITians and here to help you in your IIT JEE preparation. All the best.
If you like this answer please approve it....
win exciting gifts by answering the questions on Discussion Forum
Sagar Singh
B.Tech IIT Delhi
Dear student,
13.86/n^2=2.86
From here calculate the value of n.
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