The electron in a hydrogen atom is in the first excited state, when the electron acquires an additional 2.86eV of energy. What is the quantum number n of the state into which the electron moves?

Dear karthik,

En=-(13.6eV) * (z^2 / (nfinal)^2 - (ninitial)^2)

En=-2.86
z=1
ninitial=2

then nfinal comes out to be 5

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Sagar Singh

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Dear student,

13.86/n^2=2.86

From here calculate the value of n.

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Sagar Singh

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Dear student,

Your query has been solved...please post your same doubt only once...

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