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MI of a ring is mr^2. If we treat rings as elements of a disc as well as of a hemisphere,then MI of a disc and of hemisphere should be same (becoz mass as well as perp. distance of every corresponding ring in both from the axis will be same , but actually not. What is wrong in the concept? (here axis is the axis passing through centre and perp. to plane in both cases)
MI of a ring is mr^2.
If we treat rings as elements of a disc as well as of a hemisphere,then MI of a disc and of hemisphere should be same (becoz mass as well as perp. distance of every corresponding ring in both from the axis will be same , but actually not. What is wrong in the concept?
(here axis is the axis passing through centre and perp. to plane in both cases)
Dear neeru it is because of that for same mass and radius surface area of disk and hemisphear is not same for disk we right =dm = (M/πR2 ) 2πrdr and for the hemisphear =dm = (M/2πR2) (2πRsinΘ)(RdΘ) here we should consider that in case of dish ,element area is a area of ring which is a plane surface but in case of hemisphear element area is not plane urface it is a curved surface. Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
Dear neeru
it is because of that for same mass and radius surface area of disk and hemisphear is not same
for disk we right =dm = (M/πR2 ) 2πrdr
and for the hemisphear =dm = (M/2πR2) (2πRsinΘ)(RdΘ)
here we should consider that in case of dish ,element area is a area of ring which is a plane surface
but in case of hemisphear element area is not plane urface it is a curved surface.
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
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