The trajectory of a particle moving in xy-plane is y=x³-3x²-4x+12. The particle crosses the x-axis :

a)Once

b) Twice

c) Three times

d) Four times

Dear abhingya

y=x³-3x²-4x+12

f(x)= x³-3x²-4x+12

f(-2) =0

f(2) =0

f(3) =0

clearly it cut the x axis at three points

Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin