I cant upload the image due to some problems but i can explain it

the wire is infinite ,and a square coil is present at side of lenght a and its center is at d distant from infinite loop.

The current I₂ is passing in infinite wire upwards and I1 is current in square loop.

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The B ?eld is into the page everywhere on the right of the wire in the plane of the square loop. Its magnitude is given by B = µ0 I2 /2πR,
where R is the distance to the wire.
The above explanation shows the forces on the left and right hand side of the loop from this ?eld. These forces are obtained from
F = I_l × B, and the magnitudes are
F_left = I₁ aB = I1 a* { µ₀I₂/ (2π(d − a/2)) }
F_right= I₁ aB = I1 a* { µ₀I₂/ (2π(d + a/2))}

There is also an upward force (Ftop ) and (Ftop ), but they
are equal in magnitude and oppositely directed. Hence the
net force is the vector sum of the forces to the left and to
the right. The net force is to the left and has magnitude

F_left − F_right = { µ₀ I₁ I₂ a/2Pi}*{1/(d − a/2) - 1(d+a/2) }
                    =  { µ₀ I₁ I₂ a/2Pi}*{ a² / (d²- a2/4) }

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regards

Ramesh