Flag General Physics> power...
question mark

a tube well pumps 2400 kg/mins .if the water is coming out with velocity 3m/s.what is the power of the pump?

Omkar ajit Darekar , 16 Years ago
Grade 9
anser 2 Answers
Ramesh V

power =  force* velocity

force exerted on water in 1 sec = F = m*(v/t)

                                                   =(2400/60)*(3/1) = 120 N

power exerted = F*v=120*3=360 W

--

regards

Ramesh

Last Activity: 16 Years ago
Harish
Mass of water pumped out per sec = 2400/60 = 40 kg/sPower of pump = kinetic energy of water coming out per sec = mv^2/2 = 180 J Harish kaswan
Last Activity: 8 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments