a tube well pumps 2400 kg/mins .if the water is coming out with velocity 3m/s.what is the power of the pump?

power =  force* velocity

force exerted on water in 1 sec = F = m*(v/t)

                                                   =(2400/60)*(3/1) = 120 N

power exerted = F*v=120*3=360 W

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regards

Ramesh

Mass of water pumped out per sec = 2400/60 = 40 kg/sPower of pump = kinetic energy of water coming out per sec = mv^2/2 = 180 J Harish kaswan