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sand drops vertically at rate 2kg/sec on a conveyer belt moving with 0.2m/s horizontally. what is extra force required and rate of change of kinetic energy?

sand drops vertically at rate 2kg/sec on a conveyer belt moving with 0.2m/s horizontally. what is extra force required and rate of change of kinetic energy?

Grade:11

2 Answers

SAGAR SINGH - IIT DELHI
879 Points
10 years ago

Dear student,

Extra force required = 2*0.2=0.4 N....

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Askiitians Expert

Sagar Singh

B.Tech, IIT Delhi

Sangeeta
14 Points
2 years ago
We know that, F=dp/dt
And dp=d(mv)=vdm
Therefore, F=vdm/dt (dm/dt= 2kg/sec..Given)
F= 0.2×2= 0.4
•°• F=0.4 Newton

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