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Grade upto college level General Physics

If the binding energy per nucleon in 3Li7 and 2He4 nuclei are respectively 5.60 MeV and 7.06 Me V, then the energy of proton in the reaction 3Li7 + p --->2 2He4 is

(a) 19.6 MeV

(b) 2.4 MeV

(c) 8.4 MeV

(d) 17.3 MeV

Profile image of Amit Saxena
12 Years agoGrade upto college level
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3 Answers

Profile image of Amit Saxena
12 Years ago

(d)

Applying principle of energy conservation, Energy of proton

=      total B.E. of 2a - energy ofLi7

=      8 × 7.06 - 7 × 5.6

=      56.48 - 39.2 = 17.28 MeV

Profile image of Anurag Thamke
7 Years ago
By applying principle ofel energy conservation,   
Total binding energy of product -energy of lithium 
=8×7.60 - 7×5.6
=56.48-) - 39.2 =17.28
 
 
Profile image of Rishi Sharma
6 Years ago
Dear Student,
Please find below the solution to your problem.

Q=2(4×7.06)−7×(5.60)
=(56.48−39.2)MeV
=17.28MeV
=17.3MeV

Thanks and Regards