Flag General Physics> -binding-energy...
question mark

If the binding energy per nucleon in 3Li7 and 2He4 nuclei are respectively 5.60 MeV and 7.06 Me V, then the energy of proton in the reaction 3Li7 + p --->2 2He4 is

(a) 19.6 MeV

(b) 2.4 MeV

(c) 8.4 MeV

(d) 17.3 MeV

Amit Saxena , 12 Years ago
Grade upto college level
anser 3 Answers
Amit Saxena

(d)

Applying principle of energy conservation, Energy of proton

=      total B.E. of 2a - energy ofLi7

=      8 × 7.06 - 7 × 5.6

=      56.48 - 39.2 = 17.28 MeV

Last Activity: 12 Years ago
Anurag Thamke
By applying principle ofel energy conservation,   
Total binding energy of product -energy of lithium 
=8×7.60 - 7×5.6
=56.48-) - 39.2 =17.28
 
 
Last Activity: 7 Years ago
Rishi Sharma
Dear Student,
Please find below the solution to your problem.

Q=2(4×7.06)−7×(5.60)
=(56.48−39.2)MeV
=17.28MeV
=17.3MeV

Thanks and Regards
Last Activity: 5 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments