Force F is given in terms of time t and distance ‘x’ by F = A sin Ct + B cos Dx. Then dimensions of A/B and C/D are

        (a)    [M⁰L⁰T⁰], [M⁰L⁰T^–1]

        (b)    [MLT^–2], [M⁰L^–1T⁰]

        (c)    [M⁰L⁰T⁰], [M⁰LT^-1]

        (d)    [M⁰L^–1T^-1], [M⁰L⁰T⁰]

Question

Force F is given in terms of time t and distance ‘x’ by F = A sin Ct + B cos Dx. Then dimensions of A/B and C/D are

(a) [M⁰L⁰T⁰], [M⁰L⁰T^–1]

(b) [MLT^–2], [M⁰L^–1T⁰]

(c) [M⁰L⁰T⁰], [M⁰LT^-1]

(d) [M⁰L^–1T^-1], [M⁰L⁰T⁰]

Simran Bhatia · Answer

(a) A/B=Force/Force [M^o L^o T^o ] ct = angle C = angle/time=1/T=T^(-1) Dx = angle D = angle/distance=1/L = L&ndash;1 C/D=T^(-1)/L^(-1) =[M^o LT^(-1) ]

ankit singh · Answer

A/B= no dimensions, C/D= LT^(-1) Explanation: obviously...Ct & Dx indicate the angles Ct = radians Dx = radians C = radians/sec D = radians/metre since sinCt & sinDx are simply numericals hence A & B indicate Force components A = Newtons B = Newtons Now, C/D = [radions/sec]/radions/metre]= metre/sec = LT^(-1) A/B = Newtons/Newtons is a ratio and no dimensions

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Force F is given in terms of time t and distance ‘x’ by F = A sin Ct + B cos Dx. Then dimensions of A/B and C/D are (a) [M 0 L 0 T 0 ], [M 0 L 0 T –1 ] (b) [MLT –2 ], [M 0 L –1 T 0 ] (c) [M 0 L 0 T 0 ], [M 0 LT -1 ] (d) [M 0 L –1 T -1 ], [M 0 L 0 T 0 ]

2 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on General Physics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship