concept-and-application-of-newton-s-law-of-motion

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Aditi Chauhan · Accepted Answer

Since total mass of the system is 12 kg, so acceleration of system as whole 24/12 = 2 m/s2.Since the system is rigid the rod as well as block will have this acceleration.Now, if we take free body diagram of rod and block.Where F1 in the internal force on the contact force between rod and block, and we order blockF1 = 10 &times; 2 = 20 NSo, contact force is 20 N.

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General Physics> concept-and-application-of-newton-s-law-o...

Jitender Pal , 11 Years ago

Aditi Chauhan

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