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A man pulls one end of a rigid rod attached to a block of mass 10 kg on a smooth horizontal surface with a force of F1 = 24N horizontally. The rod has a mass of 2 kg. Find the contact force between rod and the block.
Since total mass of the system is 12 kg, so acceleration of system as whole 24/12 = 2 m/s2.
Since the system is rigid the rod as well as block will have this acceleration.
Now, if we take free body diagram of rod and block.
Where F1 in the internal force on the contact force between rod and block, and we order block
F1 = 10 × 2 = 20 N
So, contact force is 20 N.
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