Shane Macguire
Last Activity: 11 Years ago
(a) Let R be the interaction force and F1 and F2 be the frictional force on m1 and m2, respectively.
m1a = m1g sin θ + R – µ1N1 m2a = m2g sinθ – R – µ2N2
N1 – m1gcosθ = 0 N2 – N2 – µ2 cosθ = 0
(b) The two masses begin to slide just when the acceleration of m1 is not zero.
The limiting case is given by
m1g sinθmin + R – µ1m1g cosθmin = 0
Using R from part (a)