A man of mass M having a bag of mass m slips from the roof of a tall building of height H and starts falling vertically. When at a height h from the ground he notices that the ground below him is pretty hard, but there is a pond at a horizontal distance x from the line of fall. In order to save himself he throws the bag horizontally (with respect to himself) in the direction opposite to the pond. Calculate the minimum horizontal velocity imparted to the bag so that the man lands in the water. If the man just succeeds to avoid the hard ground, where will the bag land?
Ankit Barnwal , 11 Years ago
Grade 11
1 Answers
Rahul verma
Last Activity: 11 Years ago
The man falls H-h distance.v^2 - u^2 = 2as ; u=0v = { 20 (H-h) } ^ .5Find time taken to fall the remaining distance i.e. h.This is the time in which he needs to cover horizontal diastance x. thus find horizontal velocity needed.Conserve momentum, mv =MV [v is speed at which bag is thrown & V is speed that the man gains]Calculate v.
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