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30sinthetha = 18
sinthetha = 18/30
= 3/5
thetha = 37''
horizontal component = 30costhetha = 30cos37
= 30 x 4/5
= 24 N
plz approve!
vert comp=18=30sin xsinx=3/5x=37 deg
30sinthetha = 18 sinthetha = 18/30 = 3/5 thetha = 37'''' horizontal component = 30costhetha = 30cos37 = 30 x 4/5 = 24 N plz approve!
thetha = 37''''
the answer can be obtained by the application of pythagoras theorem as well.
FH2 + FV2 = F2.
here FV = 18N, F = 30N.
so FH = 24N.
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