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a force of 30N is inclined at an angle of theta to the horizontal.If its vertical component is 18N. find theta and horizontal component.

larisha sharma , 12 Years ago
Grade 11
anser 5 Answers
Vikas TU

30sinthetha = 18

sinthetha = 18/30

              = 3/5

 

thetha = 37''

horizontal component = 30costhetha = 30cos37

                                                    = 30 x 4/5

                                                    = 24 N

 

plz approve!

 

ApprovedApproved
Last Activity: 12 Years ago
Akash Kumar Dutta

vert comp=18=30sin x
sinx=3/5
x=37 deg

Last Activity: 12 Years ago
Abhishekh kumar sharma

30sinthetha = 18

sinthetha = 18/30

              = 3/5

 

thetha = 37''''

horizontal component = 30costhetha = 30cos37

                                                    = 30 x 4/5

                                                    = 24 N

 

plz approve!

 

Last Activity: 12 Years ago
SOURAV MISHRA

the answer can be obtained by the application of pythagoras theorem as well.

FH2 + FV2  = F2.

here FV = 18N, F = 30N.

so FH = 24N.

Last Activity: 12 Years ago
Divy Patel
37 degree APPROX
 , 24 NEWTON..................,.....................................................................................................................................................
Last Activity: 3 Years ago
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