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max resultant of two forces x and yy is x+y and min of the two forces is x-y
x+y=16
x-y=4
=>x=10N y=6N
let the two vector be a and b then maxm resultant would be a+b=16 and minm resultant would be a-b=4...solve these two eqns and u will get the answer i.e. 10 and 6...
10,6
but for adding 2 vector ..formula is[ a2 + b2 +2abcos thetA]^1/2 OVER HERE WE DO NOT KNOW THETA
??but for adding 2 vector ..formula is[ a2 + b2 +2abcos thetA]^1/2 OVER HERE WE DO NOT KNOW THETA...
see in case of maxm resultant we take theta equals to 0degree i.e. cos(theta)=1
n in case of minm resultant we take theta = 180 degree i.e. cos(theta)=-1
CLEARLY YOU HAVE TO SOLVE A SYSTEM OF SIMULTANEOUS EQUATIONS. THIS IS VERY EASY AND I WILL MENTION THE ANSWER DIRECTLY.
THE GREATER ONE IS 10N AND THE SMALLER ONE IS 6N.
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