the maximum and minimum magnitude of the resultant of two forces are 16 N and 4N.calculate t he magnitude of individual force.

max resultant of two forces x and yy is x+y and min of the two forces is x-y

x+y=16

x-y=4

=>x=10N y=6N

let the two vector be a and b then maxm resultant would be a+b=16 and minm resultant would be a-b=4...solve these two eqns and u will get the answer i.e. 10 and 6...

10,6

but for adding 2 vector ..formula is[ a2 + b2 +2abcos thetA]^1/2    OVER HERE WE DO NOT KNOW THETA

??but for adding 2 vector ..formula is[ a2 + b2 +2abcos thetA]^1/2    OVER HERE WE DO NOT KNOW THETA...

see in case of maxm resultant we take theta equals to 0degree i.e. cos(theta)=1

n in case of minm resultant we take theta = 180 degree i.e. cos(theta)=-1

CLEARLY YOU HAVE TO SOLVE A SYSTEM OF SIMULTANEOUS EQUATIONS. THIS IS VERY EASY AND I WILL MENTION THE ANSWER DIRECTLY.

THE GREATER ONE IS 10N AND THE SMALLER ONE IS 6N.