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Grade 12General Physics

A metal wire of linear mass density of 9.8 g/m is stretched with a tension of 10 kg-wt between two rigid supports 1 metre apart. The wire passes at its middle point between the poles of a permanent magnet, and it vibrates in resonance when carrying an alternating current of frequency n. The frequency n of the alternating source is

Profile image of A Sreekhar
16 Years agoGrade 12
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3 Answers

Profile image of anuj kumar sharma
11 Years ago
the wire will vibrate with the same frequency as that of source .this can be considered as anexample of forced vibration.
T=10*9.8N=98N
M=9.8*10^-3Kg/m
Frequencyof wire,f=1/2Lroot(T/M)
                          f=1/2*1root(98/9.8*10^-3)
                           f=50Hz is the Answer.
Profile image of Adeeba
7 Years ago
f=1/2l√(T/m)As for1/2(1/2)/
Profile image of Adeeba
7 Years ago
The wire vibrate with the same frequency as that of source
f=1/2l√(T/m)
As the wire is at the middle point l=1/2
f=(2/2)/√(10*9.8)/9.8*10^-3
f=100