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what is the de-broglie wavelength of electron of energy 180ev

anusha sista , 12 Years ago
Grade 12
anser 5 Answers
Akash Kumar Dutta

Last Activity: 12 Years ago

apply lambda=hc/E...where E=180eV

Chetan Mandayam Nayakar

Last Activity: 12 Years ago

p2/2m=E, p=sqrt(2mE),λ=h/(2π)

Vikas TU

Last Activity: 12 Years ago

For de-broglie wavelength 

lamda = underoot 150/V 

where V is the Voltage

Lamda = underroot150/180

          = underroot5/6 is the ansr.

Abhishekh kumar sharma

Last Activity: 12 Years ago

we have e=hv    ... 1

and v=c\λ

substitue v in 1 to get e=hc\λ

then lambda =hc\e

Sukumar Adepu

Last Activity: 11 Years ago

9 * 10 power -11

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