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apply lambda=hc/E...where E=180eV
p2/2m=E, p=sqrt(2mE),λ=h/(2π)
For de-broglie wavelength
lamda = underoot 150/V
where V is the Voltage
Lamda = underroot150/180
= underroot5/6 is the ansr.
we have e=hv ... 1
and v=c\λ
substitue v in 1 to get e=hc\λ
then lambda =hc\e
9 * 10 power -11
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