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a bottom of a vessel has a small opening of area A. A disk is held against the opening to keep the liquid from flowing out. let F1 be the net force on the disk applied by the liquid and air in this case. now the disk is moved away from the opening a short distance.the liquid comes out and strikes the disk inelsticallly.let F2 be the force exerted by the liquid in this case. then F1/F2 is?

harshini k , 12 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To understand the relationship between the forces F1 and F2 in this scenario, we need to analyze the forces acting on the disk both when it is held against the opening and when it is moved away, allowing the liquid to flow out. This involves concepts from fluid dynamics and Newton's laws of motion.

Analyzing the Forces

Initially, when the disk is held against the opening, the net force F1 acting on the disk is a result of the pressure exerted by the liquid inside the vessel and the atmospheric pressure acting on the disk. The pressure difference across the disk creates a force that keeps it in place. This can be expressed as:

  • F1 = P_liquid * A - P_atmospheric * A

Here, P_liquid is the pressure of the liquid inside the vessel, P_atmospheric is the atmospheric pressure, and A is the area of the opening. The net force F1 is essentially the force required to keep the disk in position against the pressure of the liquid.

When the Disk is Moved

Now, when the disk is moved away from the opening, the liquid begins to flow out due to the pressure difference. The liquid strikes the disk inelastically, meaning that the liquid does not bounce off but rather sticks to the disk momentarily. The force F2 exerted by the liquid on the disk during this impact can be understood through the concept of momentum change.

When the liquid exits the vessel, it has a certain velocity (v) determined by the height of the liquid column and the area of the opening. The force F2 can be related to the rate of change of momentum of the liquid striking the disk:

  • F2 = (Δ(mv))/Δt

Where Δ(mv) is the change in momentum of the liquid and Δt is the time interval during which the liquid strikes the disk. The liquid's mass flow rate (mass per unit time) can be expressed as:

  • mass flow rate = ρ * A * v

Here, ρ is the density of the liquid. Thus, we can express F2 in terms of the liquid's properties and the area of the opening.

Comparing the Forces

To find the ratio F1/F2, we can substitute our expressions for F1 and F2:

  • F1/F2 = (P_liquid * A - P_atmospheric * A) / (ρ * A * v)

Notice that the area A cancels out in the ratio, simplifying our expression. This means that the ratio of the forces depends on the pressure difference and the properties of the liquid rather than the area of the opening itself.

Final Thoughts

In summary, the ratio F1/F2 reflects the balance between the pressure forces acting on the disk and the dynamic forces exerted by the liquid as it flows out. This relationship is crucial in understanding fluid behavior in various applications, such as in engineering and environmental science. By analyzing these forces, we gain insights into how fluids interact with solid surfaces, which is fundamental in many scientific and practical contexts.

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