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the diameter of the wire as measured by screw guage was found to be 2.620 , 2.625 , 2.628 , 2.626 . calculatea) mean value of diameterb) absolute error in each measurec) mean absolute errord) fractional errore) percentage errorf express the result in terms of percentage error.

shivam chopra , 11 Years ago
Grade 11
anser 1 Answers
Apoorva Arora

Last Activity: 10 Years ago

We have a set of four values:

2.620, 2.625, 2.628,2.626
therefore mean:
hence absolute error is given by:
= .005, 0, .003, .001
hence mean absolute error is:
Now, Fractional error is given by
= .0019, 0, .0011, .0004
and further, percentage error is given by
=.19%, 0%, .11%, .04%

Thanks and Regards
Apoorva Arora
IIT Roorkee
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