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the diameter of the wire as measured by screw guage was found to be 2.620 , 2.625 , 2.628 , 2.626 . calculate a) mean value of diameter b) absolute error in each measure c) mean absolute error d) fractional error e) percentage error f express the result in terms of percentage er ror.

the diameter of the wire as measured by screw guage was found to be 2.620 , 2.625 , 2.628 , 2.626 . calculate


a) mean value of diameter


b) absolute error in each measure 


c) mean absolute error


d) fractional error


e) percentage error


f express the result  in terms of percentage error.

Grade:11

1 Answers

Apoorva Arora IIT Roorkee
askIITians Faculty 181 Points
9 years ago
We have a set of four values:
2.620, 2.625, 2.628,2.626
therefore mean:
hence absolute error is given by:
= .005, 0, .003, .001
hence mean absolute error is:
Now, Fractional error is given by
= .0019, 0, .0011, .0004
and further, percentage error is given by
=.19%, 0%, .11%, .04%

Thanks and Regards
Apoorva Arora
IIT Roorkee
askIITians Faculty

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