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the position of an object is given by Y= t^3- 6t^2+9t+5 Find the distance covered in 5 secs


  the position of an object is given by


Y= t^3- 6t^2+9t+5


Find the distance covered in 5 secs

Grade:11

2 Answers

sourav singh
29 Points
8 years ago
first of all we put t=0 so we get position of the object 5. now putting t=5 we get position=205 so distance covered=205-5=200. ans=200
tejas naresh patel
40 Points
8 years ago

720 m in opposite direction

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