Grade 11General Physics
the position of an object is given by
Y= t^3- 6t^2+9t+5
Find the distance covered in 5 secs
the position of an object is given by
Y= t^3- 6t^2+9t+5
Find the distance covered in 5 secs
2 Answers
sourav singh
first of all we put t=0 so we get position of the object 5.
now putting t=5 we get position=205
so distance covered=205-5=200.
ans=200
tejas naresh patel
720 m in opposite direction
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