Askiitians Expert Bharath-IITD
Last Activity: 15 Years ago
Dear Sachin,
Generally in the cases of motion of the string in circular motion with one end of tied to an object, the object experiences the forces in equilibrium.
1. Force due to the rotational motion .ie. centripetal force--- Fr=mv2/r,
2. Force due to gravity --- F = mg,
3. Tension in the string T.
Now when we are rotating at low speeds where Fr and F are comparable then the object will rotate making angle θ with the vertical such that the resultant force FT = √[ Fr2 + F2] is balanced by the tension in the string T.
We also have tan θ = Fr /F
So we spin the object such that its contribution to the square sum is more than the force due to gravity then the object becomes horizontal thus there is no necesscity to balance the gravitational force as it is negligible.
So when Fr is very large then θ = 900
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Adapa Bharath
