Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Which force balance the weight of object, when it is tied at one end of string and rotated horizontally exactly in a plane parallel to ground?

Which force balance the weight of object, when it is tied at one end of string and rotated horizontally exactly in a plane parallel to ground?

Grade:Upto college level

2 Answers

Askiitians Expert Bharath-IITD
23 Points
11 years ago

Dear Sachin,

Generally in the cases of motion of the string in circular motion with one end of tied to an object, the object experiences the forces in equilibrium.

1. Force due to the rotational motion .ie. centripetal force--- Fr=mv2/r,

2. Force due to gravity --- F = mg,

3. Tension in the string T.

Now when we are rotating at low speeds where Fr and F are comparable then the object will rotate making angle θ with the vertical such that the resultant force FT = √[ Fr2 + F2] is balanced by the tension in the string T.

We also have tan θ = Fr /F

So we spin the object such that its contribution to the square sum is more than the force due to gravity then the object becomes horizontal thus there is no necesscity to balance the gravitational force as it is negligible.

So when Fr is very large then θ = 900

Please feel free to post as many doubts on our discussion forum as you can. If you find any question
Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We
are all IITians and here to help you in your IIT JEE preparation.


All the best !!!

 


Regards,

Askiitians Experts

Adapa Bharath

5856-1617_8384_Untitled.jpg

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear Sachin

Resultant of Weight and centrifugal force is balance by tension in spring

when rotation speed is very high then

centrifugal force is very large compair to weight of the mass. angle made by string in this case with the vertical is almost 90 degree(not equal to 90).

string not rotated horizontly but with a very small angle with horizontal.

if sting is not completly horizontal then its tension must have vertical component also which balance the weight of the mas

 

Regards

Badiuddin

 

 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free