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Q1. from a square sheet of uniform density a portion is removed .find the centre of mass of the remaining portion if the side of the square is A. Q1. from a square sheet of uniform density a portion is removedĀ .find theĀ centre of mass of the remaining portion if the side of the square is A.Ā
Q1. from a square sheet of uniform density a portion is removedĀ .find theĀ centre of mass of the remaining portion if the side of the square is A.Ā
simran wd u plz tell me at kind of a portion u mean?
Let m1 be the Ī±*aĀ² and m2 be the Ī±*aĀ²/4 where Ī± be the uniform mass density From the question, we have to find the centre of mass of remaining portion. Now we have Xcm = m1*x1 +m2*x2 /m1+m2=( Ī±*aĀ²*0 - Ī±*aĀ²/4*a/2)/Ī±*aĀ²+Ī±*aĀ²= -aĀ³*Ī±/8*4Ī±*aĀ²/5= -a/10There was no possibility to create a diagram
x Ć mass remaining = mass removed Ć side/total no. of unshade sides(m-m/4) Ć x = (m/4)(a/3)X=a/3
sorry(3m/4)x=(m/4)(a/3)Answer=ćx=a/9In above answer I have done a small error in solving ,this is the correct answer š.Ā
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