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Grade: 12

                        

a rope 1 cm in diameter breaks if tension in it exceed 500N.the maximum tension given to similar rope of diameter 2 cm??/

10 years ago

Answers : (1)

Jitu Jitesh Pancholi
28 Points
							
So, basically this is a question of young's modulus and its formula. 
as you know that young's modulus = (tension*original length)/(cross sectional area*change in length) 

since in this question all the quantities except tension and area are constant we can say that tension∝area of cross section. 
thus tension∝D² (as area = πD²/4 ; D is diameter) 
so if for D =1 tension = 500N 
then for D = 2 tension will be four times i.e tension = 2000N. 
if you like my answer please choose it as the best! .thanx. ;-)
3 years ago
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