45km/hr.
						

							
Hi Anurag you posted a question on the two cars moving in same direction with same velocity 30km/hr , but how can the third car meet both cars after the given time interval if both have same velocity and have 5m of initial distance.
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BEST OF LUCK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
 
						

							
velocity of A wrt C = va-vc
at time t=0 car C met car B
at t=4/60 hrs. car A will meet Car C. 
distance traveled by Car A = 5km
=> 5= (Va-Vc)4/60
300/4= 30- Vc
75- 30 = - Vc
Vc = -45 kmph. (- shows opposite direction)
all the best!
 
						

							
yes i can provide more satisfactory answer tu pagal hai doubt click here provide a better answer and ea
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The two cars are moving in same direction with same speed. So let the speed of two cars be v Km/h and velocity of car moving in opposite direction be u Km/h. So, total speed= total distance/ time= 5/1/15 (4 minutes= 4/60= 1/15 hrs.). So we will get total speed as 75 km/h. Therefore, v+u= 75 I.e., u= 75-30= 45 km/h i.e., the speed of car moving in opposite direction is 45 km/h.