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Grade:
        the height above the surface of earth where g decreases to 9% of its maximum value on earth surface is.(radius of earth 6400 km)
10 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
							

Dear anand s

g=G Me/(Re +h)2

 wher h is hight from earth surface

value of g on earth  surface is for h=0

g1=G Me/(Re )2

 

so we need to find g such that

 g=.09 g1

G Me/(Re +h)2   =.09G Me/(Re )2

or Re =.3 (Re+h)

h=7Re/3

 


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Badiuddin

10 years ago
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