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A rope of length L is pulled with a constant force F. T is the tension in the rope at a point distance x from the end where the force is applied. Then T is: (a) FL/x (b) FL/(L - x) (c) F (L - x)/L (d) (F - x) / (L - x)


A rope of length L is pulled with a constant force F. T is the tension in the rope at a point distance x from the


end where the force is applied. Then T is:


(a) FL/x (b) FL/(L - x) (c) F (L - x)/L (d) (F - x) / (L - x)


Grade:11

1 Answers

Aman Bansal
592 Points
8 years ago

Dear Jeet,

If the string is equally pulled at each end, the tension will be constant all the way through.

You only get a different effect if you use a heavy string to accelerate an object across a surface for example.

EG: suppose you have a 9kg mass connected to a 1kg rope, and a 10 N force is applied to the free end of the rope.

You are applying a 10 N force to a 10 kg load, so should achieve accelersation of 1 ms-2

The end of the rope that you are pulling will have a tension of 10 N

Down the other end, the rope is accelerating a 9kg mass at 1 ms-2 so clearly the tension there is only 9 N.

Half way along the rope, the Tension will be 9.5 N

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Askiitian Expert


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