Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A monkey of mass 20 Kg is holding a vertical rope. The rope can break when a mass of 25 Kg is suspended from it. What is the maximum acceleration with which the monkey can climb up along the rope? (a)2.5 ms-2 (b) 5 ms-2 (c) 7 ms-2 (d) 10 ms-2


A monkey of mass 20 Kg is holding a vertical rope. The rope can break when a mass of 25 Kg is suspended


from it. What is the maximum acceleration with which the monkey can climb up along the rope?


(a)2.5 ms-2 (b) 5 ms-2 (c) 7 ms-2 (d) 10 ms-2


Grade:11

8 Answers

Anirban Mukherjee
47 Points
9 years ago
Let the monkey climb up with acceleration a. Then tension caused in the rope will be T =

M(g+a), where M is the mass of the monkey. Maximum value of T is 25g = 20(g + a). Taking

g = 10ms

-2, it gives a = 2.5 ms
Aman Bansal
592 Points
9 years ago

Dear Jeet,

assuming the value of g is 10ms^-2, the maximum weight that the rope can hold is  

25kg×10Nkg1=250N

. (though it should be less than 250, I''m not so sure about the maimum part) using F=ma,

a=250N20kg =12.5ms2

The maximum acceleration of the monkey is 12.5ms^-2

Cracking IIT just got more exciting,It s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and win by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple  to download the toolbar….

So start the brain storming…. become a leader with Elite Expert League ASKIITIANS

Thanks

Aman Bansal

Askiitian Expert

somy chaturvedi
10 Points
9 years ago

tension is responsiblefor upward acc. and  maximum tension it can bear is 250N. hence max acc.

250-200=20*a

a=2.5m/s^2

sheik arbaz
38 Points
9 years ago

2.5 m/s-2

Shahvar Tyagi
26 Points
5 years ago
A monkey of mass 20 kg. is holding a vertical rope. The rope will not break when a mass of 25 kg. is suspended from it but will break if the mass exceeds 25 kg. What is the maximum acceleration it which the monkey can climb up along the rope
Ajinkya kawale
11 Points
4 years ago
let the initial tension be Tusing fbd for m=20kg we get,T-mg=maT-20g=20a…1Tmax-25g=0Tmax=25g……2from 1,225g-20g=20a5g=20aa=g/4 =2.5m/s^2hope this helps…
Vicky Singh
13 Points
2 years ago
1kgf = 1kg * 10m/s square 
         =10N
For 25kgf=25kg * 10m/s square 
                =250N _____(1)
 Monkey mass =20kg so mg=200N (2)
      Subtract equation 2 from 1 we get 
        250N-200N=50N
      Force = Mass *acceleration 
       50 =20kg * a
       a = 2.5 m/s square 
              
Rishi Sharma
askIITians Faculty 646 Points
one year ago
Dear Student,
Please find below the solution to your problem.

1kgf = 1kg * 10m/s square
=10N
For 25kgf=25kg * 10m/s square
=250N _____(1)
Monkey mass =20kg so mg=200N (2)
Subtract equation 2 from 1 we get
250N-200N=50N
Force = Mass *acceleration
50 =20kg * a
a = 2.5 m/s square

Thanks and Regards

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free