Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A BALL OF MASS 100g and having a charge of 40*10^-5 is relesed from rest in aregion where horizontal E.F of 2*10^4 N/C exists. a)find the resulting force acting on the ball. b) whay will be the path of the ball C) where will be the ball at the end of 2seconds
There will ne a vertical force acting downwards = mg=1 newtonand one horizontal force towards the right, say, = Eq= 8 newtonso the resultant force isand the angle made by the resultant force will beand hence it will move along a straight line with an angle of 82.8 degrees with the verticalSo after 2 seconds= 160 mand=20 massuming that the origin is the position of ball at t=0 and the x axis increases towards the right and y axis increases towards the downward direction.Thanks and RegardsApoorva AroraIIT RoorkeeaskIITians Faculty
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -