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Grade: 12
        

A BALL OF MASS 100g and having a charge of 40*10^-5 is relesed from rest in aregion where horizontal E.F of 2*10^4 N/C exists. a)find the resulting force acting on the ball. b) whay will be the path of the ball C) where will be the ball at the end of 2seconds

7 years ago

Answers : (1)

Apoorva Arora
IIT Roorkee
askIITians Faculty
181 Points
							There will ne a vertical force acting downwards = mg=1 newton
and one horizontal force towards the right, say, = Eq= 8 newton
so the resultant force is
and the angle made by the resultant force will be
and hence it will move along a straight line with an angle of 82.8 degrees with the vertical
So after 2 seconds
= 160 m
and
=20 m
assuming that the origin is the position of ball at t=0 and the x axis increases towards the right and y axis increases towards the downward direction.

Thanks and Regards
Apoorva Arora
IIT Roorkee
askIITians Faculty
5 years ago
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