ELECTRIC FEILD

Question

A BALL OF MASS 100g and having a charge of 40*10^-5 is relesed from rest in aregion where horizontal E.F of 2*10^4 N/C exists. a)find the resulting force acting on the ball. b) whay will be the path of the ball C) where will be the ball at the end of 2seconds

Apoorva Arora · Accepted Answer

There will ne a vertical force acting downwards = mg=1 newton

and one horizontal force towards the right, say, = Eq= 8 newton

so the resultant force is

$F_{net}=\sqrt{F_{1}^{2}+F_{2}^{2}+2F_{1}F_{2}cos\theta }=\sqrt{65}newton$

and the angle made by the resultant force will be $cos^{-1}\frac{1}{8}$

and hence it will move along a straight line with an angle of 82.8 degrees with the vertical

So after 2 seconds

$x=\frac{1}{2}\frac{F}{m}2^{2}$ = 160 m

and

$y=\frac{1}{2}\frac{F}{m}2^{2}$ =20 m

assuming that the origin is the position of ball at t=0 and the x axis increases towards the right and y axis increases towards the downward direction.

Thanks and Regards

Apoorva Arora

IIT Roorkee

askIITians Faculty

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General Physics> ELECTRIC FEILD...

A BALL OF MASS 100g and having a charge of 40*10^-5 is relesed from rest in aregion where horizontal E.F of 2*10^4 N/C exists. a)find the resulting force acting on the ball. b) whay will be the path of the ball C) where will be the ball at the end of 2seconds

munnuri ratnakumar , 13 Years ago

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LIVE ONLINE CLASSES

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