Last Activity: 12 Years ago
given
mg-fair=ma (i)
acording to the question;
fair-(m-x)g=(m-x)a (ii)
(i)+(ii) gives usg(m-m+x)=a(m+m-x)
gx/a=2m-x
x(g/a+1)=2m
solving for x immidiately gives us
x(g+a)/a=2m
x=(2ma)/(g+a)
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Last Activity: 2 Years ago