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A balloon of total mass m is descending with an acceleration of a. Find the mass that removed from the balloon such that it ascends with the same acceleration a. Answer must be in terms of a,g(accelearion due to gravity) and m
given mg-fair=ma (i) acording to the question; fair-(m-x)g=(m-x)a (ii) (i)+(ii) gives usg(m-m+x)=a(m+m-x) gx/a=2m-x x(g/a+1)=2m solving for x immidiately gives us x(g+a)/a=2m x=(2ma)/(g+a)
given
mg-fair=ma (i)
acording to the question;
fair-(m-x)g=(m-x)a (ii)
(i)+(ii) gives usg(m-m+x)=a(m+m-x)
gx/a=2m-x
x(g/a+1)=2m
solving for x immidiately gives us
x(g+a)/a=2m
x=(2ma)/(g+a)
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