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A body of mass M kg is falling from a height h meters hits another body of mass M kg placed on sandy patch of ground at rest and sticks to it. The work done before the combined mass comes to rest after penetrating a depth d in the sand will be A)Mgh/2 B)2Mgh?2?/d C)Mgh?2?/d D)Mgd?2?/h plzz reply fast
the collision between the two bodies is perfectly inelastic. Therefore, kinetic energy immediately after collision=Mgh/2 therefore answer=A)Mgh/2
the collision between the two bodies is perfectly inelastic. Therefore, kinetic energy immediately after collision=Mgh/2
therefore answer=A)Mgh/2
answer:- A (Mgh/2)
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