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two cars are moving in the same direction with speed 10 m/s and 12m/s. car with velocith 10 m/s is ahead. when the sepration was 200 mthe backward car decided to acclerate to avoid accident. was should be the minimum value of accleration t avoid accleration?
12 m/s 10m/s
A------> B------>
<---------------------->
200m
working in reference frame attached to B
velocity of A wrt B is 12-10= 2 m/s.
Let acceleration (rather deceleration) of A be a m/s^2.
now, v^2 - u^2=2as
0 - 2^2= 2(a) 200
-4/400= a
therefore, a(min.) = -0.01 m/s^2.
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