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two cars are moving in the same direction with speed 10 m/s and 12m/s. car with velocith 10 m/s is ahead. when the sepration was 200 mthe backward car decided to acclerate to avoid accident. was should be the minimum value of accleration t avoid accleration?

saurav sharma , 12 Years ago
Grade
anser 1 Answers
rupali sehgal

Last Activity: 12 Years ago

12 m/s                     10m/s

A------>                    B------>

 <---------------------->

           200m

working in reference frame attached to B

velocity of A wrt B is 12-10= 2 m/s.

Let acceleration (rather deceleration) of A be a m/s^2.

now, v^2 - u^2=2as

0 - 2^2= 2(a) 200

-4/400= a

therefore, a(min.) = -0.01 m/s^2.

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