a loadw is to b raised by a rope from rest to rest through a height h. the greatest tension the rope can safely bear is nw. th eleast time in which the ascent cabn b made will be

Question

rupali sehgal · Answer

2 forces will act on the load:

1) tension upwards

2) mg downwards.

its to b pulled upwards in least time

so there must b an acceleration upwards.

let max tension be nw.

so, (nw)-mg=ma_max

a_max = (nw)-mg/m---------(1)

using equation s=ut+1/2at²

we get h= 0 + 1/2 {(nw) - mg/m}t²(from 1)

t^{2 =}2mh/(nw)-mg

t= √2mh/nw-mg

Radhey · Answer

This is not the correct answer. Since the block will first accelerate and then decelerates. In this solution you have considered only one aspect. It should be in 3 steps , acceleration, constant speed amd then deceleration. Think again

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a loadw is to b raised by a rope from rest to rest through a height h. the greatest tension the rope can safely bear is nw. th eleast time in which the ascent cabn b made will be

a loadw is to b raised by a rope from rest to rest through a height h. the greatest tension the rope can safely bear is nw. th eleast time in which the ascent cabn b made will be

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