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a balloon is ascending vertically with an acceleration of 0.2 m/s2. Two stones are dropped from it at an interval of 2sec. Find the distance between them 1.5 sec after the second stone is released. (use g=9.8)
first u have to specify the velocity of balloon when stone is dropped,let it be v, velocity of 1st stone is v in upward direction n acceleration downward, use vt - 0.5 gt2 = d using appropriate signs for directions. t=2+1.5 sec the 2nd stone will have addition separation due to movement of balloon n also additional speed use same formula with t=1.5 sec and v2 = v + time.acceleration of balloon *make a diagram with reference point as the place where 1st stone is drawn n measure distances accordingly
first u have to specify the velocity of balloon when stone is dropped,let it be v,
velocity of 1st stone is v in upward direction n acceleration downward, use
vt - 0.5 gt2 = d using appropriate signs for directions. t=2+1.5 sec
the 2nd stone will have addition separation due to movement of balloon n also additional speed
use same formula with t=1.5 sec and v2 = v + time.acceleration of balloon
*make a diagram with reference point as the place where 1st stone is drawn n measure distances accordingly
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