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```
A man crosses a river in a boat in minimum time of 10mins with a drift 120m. If he crosses in shortest path he takes 12.5mins. Find (i) width of river (ii) velocity of boat w.r.t water (iii) speed of current.

```
8 years ago

Monil Shah
34 Points
```							Width of river is 187.5,speed of boat ww.r.t is 0.25 ,velocity of current is 0.2.

All speed are in m/ s and distance in m
```
8 years ago
Arun Kumar
IIT Delhi
256 Points
```							velocity of river=120m/10min=12m/minnow for the man in second case(shortes pathvx^2+vy^2=v^2 where v is magnitude of man's velocityvy=12m/min since its the shortest pathso vx=root(v^2-12^2)for the shortest timed=10*v10v=12.5*root(v^2-12^2)v=root(12.5^2*10^2/(12.5^2-10^2))v=12*12.5/(2.5*22.5)d=10*v
```
6 years ago
KAPIL MANDAL
132 Points
```							Thank you sir for this answer. Thank you very much.
```
5 years ago
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