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A body is projected up with a velocity equal to 3/4 of the escape velocity from the surface of the earth. The height it reaches is (Raduis of Earth is R)
Dear Siva, vi=(3/4) of escape velocity from the surface of the earth = (3/4)*11200 = 8400 m/svf=0 m/st=timeg=9.8 m/s2d=distancevf=vi-gt0=vi-gtt=vi/gnow, d=(vf-vi)t/2d=(vi)^2/2gso,d= 3600000 m = 3600km Cracking IIT just got more exciting,It s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and win by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple to download the toolbar…. So start the brain storming…. become a leader with Elite Expert League ASKIITIANS Thanks Aman Bansal Askiitian Expert
Dear Siva,
vi=(3/4) of escape velocity from the surface of the earth = (3/4)*11200 = 8400 m/svf=0 m/st=timeg=9.8 m/s2d=distancevf=vi-gt0=vi-gtt=vi/gnow, d=(vf-vi)t/2d=(vi)^2/2gso,d= 3600000 m = 3600km
Cracking IIT just got more exciting,It s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and win by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple to download the toolbar….
So start the brain storming…. become a leader with Elite Expert League ASKIITIANS
Thanks
Aman Bansal
Askiitian Expert
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