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A body is projected up with a velocity equal to 3/4 of the escape velocity from the surface of the earth. The height it reaches is (Raduis of Earth is R)
Dear Siva,
vi=(3/4) of escape velocity from the surface of the earth = (3/4)*11200 = 8400 m/svf=0 m/st=timeg=9.8 m/s2d=distancevf=vi-gt0=vi-gtt=vi/gnow, d=(vf-vi)t/2d=(vi)^2/2gso,d= 3600000 m = 3600km
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