dimension of magnetic induction
reyansh garg , 12 Years ago
Grade 12th Pass
General Physics> dimension of magnetic induction
5 Answers
Digant Dubey
Last Activity: 12 Years ago
M T -2 A -1
Nikhil Cherukupalli
Last Activity: 12 Years ago
We know that F= B I L... From that we get B as F/IL = [MLT-2] / [A] [L] = [ML0T-2A-1]
Anjali kumari
Last Activity: 6 Years ago
It is equals to Magnetic field intensity vector which is equals to MT^-2A^-1.
Prabhavathi Siram
Last Activity: 5 Years ago
From the equation F= BIL ,
B= F/IL
B=magnetic induction
I= Current (in Amperes)
F= Force=ma
L= length=l
B= ma/(amp.*l)
B= MLT^-2/(A*L)
=ML°T^-2 A^-1
L=length
Rishi Sharma
Last Activity: 4 Years ago
Dear Student,
Please find below the solution to your problem.
From the equation F= BIL ,
B= F/IL
B=magnetic induction
I= Current (in Amperes)
F= Force=ma
L= length=l
B= ma/(amp.*l)
B= MLT^-2/(A*L)
=ML°T^-2 A^-1
Thanks and Regards
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