in mirror formula provem=f/f-u.
saurabh Sancheti , 12 Years ago
Grade
General Physics> regarding optics
3 Answers
Shyama P
Last Activity: 12 Years ago
1/f= 1/u+1/v
multiplying with u =>
u/f= 1+u/v
m=-v/u Sub in eqn
u/f-1=-1/m
Solve & u get the ans:
Sanandanan M
Last Activity: 12 Years ago
(1/v) + (1/u) = (1/f)
(1/v) = (1/f) - (1/u) = ((u-f)/f)
multiply throughout by -u and take reciprocal
-(v/u) = (f/(f-u))
that is magnification.
Prashant Sinha
Last Activity: 3 Years ago
Mirror Formula- 1/v+1/u=1/f
1/v=(1/f)-(1/u)
1/v=(1/f)-(1/u)
1/v=(u-f)/fu
v=fu/(u-f) ---------- (1)
v=fu/(u-f) ---------- (1)
Magnification (m) = -(v)/u
m=-(fu/(u-f))/u (From (1))
u-f can be written as -(f-u)
so it will become
m=(fu/f-u)/u
m=f/(f-u) (By cancelling u)
Hence proved.
m=-(fu/(u-f))/u (From (1))
u-f can be written as -(f-u)
so it will become
m=(fu/f-u)/u
m=f/(f-u) (By cancelling u)
Hence proved.
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