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A car with the initial velocity of 30 m/s stops at constant rate during a 6 s time interval. the distance traveled by the car during 6 s is:
Answer: 90 m
how???????
U=30M/SEC
V=0
T=6SEC
V=U-AT [RETARDATION]
0=30-A*6
A=30/6
A=5
S=UT+1/2AT2
S=O+1/2*5*36
=90
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