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the velociy at the midway point f a ball able to reach a height y when thrown with a velocity u at the origin is -
a) u/2;
b) root of [2ugy];
c) root of [u squared/2];
d) root of [u squared + 2gy ]
let answer be v
u2-v2=2g(y/2)
energy conservation at all points gives ans
√(gy)
ans c
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