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# a proton moving along the x axis moves with a constant accelaration of 6 x 10^12 m/s with initial velocity of 4x10^6 m/s . what is the velocity of proton after it travels a distance of 80cm?

Aman Bansal
592 Points
9 years ago

Dear Goutham,

using linear equations of motion
v^2-u^2=2as
given a=6*1012m/s^2~i-i~s=0i-i8m~i-i~u=4*10^6m/s
v^2=2*0i-i8*6*10^12 +(4*10^6)^2
=(9i-i6+16)*10^12
=25i-i6*10^12
thus final velocity is sqrt(25i-i6*10^12)m/m

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