Kohav Dey
Last Activity: 7 Years ago
Let the acceleration be a which is same for all drops.
Let time for 1st drop be t, 2nd drop be 2t, 3rd drop be 3t.
therefore
distance covered y 1st drop: u=0, 1/2at^2, 2nd drop : 2at^2, 3rd drop : 9at^2/2.
therefore distance between 1st and 2nd drop :3/2at^2, 2nd and 3rd drop:5/2at^2,1st and 3rd drop: 4at^2.
therefore the ratio is 3:5:4.