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Find the percentage error in specific resistance given by p=(pi*r^2*R)/l where r is the radius having value between (0.2+0.02)cm and (0.2-0.02)cm, R is the resistance of values between (60+2) and (60-2)ohm and l is the length of values between (150+0.1) and (150-0.1)cm.

Find the percentage error in specific resistance given by p=(pi*r^2*R)/l where r is the radius having value between (0.2+0.02)cm and (0.2-0.02)cm, R is the resistance of values between (60+2) and (60-2)ohm and l is the length of values between (150+0.1) and (150-0.1)cm.

Grade:11

1 Answers

Aman Bansal
592 Points
12 years ago

Daer Arnab,

Error = 2*0.02+ 2 + 0.1,

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