Guest

I was trying to solve this problem. Could anybody help me A force of 50 dynes is applied on a body of mass 5g which is at rest for an interval 1 sec. Then Impulse would be a) 0.15x10^(-13) N s b) 0.98x10^(-3) N-s c) 1.5x10^(-3) N-s d) 2.5x10^(-3)N-s

I was trying to solve this problem. Could anybody help me


A force of 50 dynes is applied on a body of mass 5g which is at rest for an interval 1 sec. Then Impulse would be


a) 0.15x10^(-13) N s


b) 0.98x10^(-3) N-s


c) 1.5x10^(-3) N-s


d) 2.5x10^(-3)N-s


 


 

Grade:9

1 Answers

Chetan Mandayam Nayakar
312 Points
10 years ago

impulse=force*time. If force is varying, impulse=∫force*dt

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free