Flag General Physics> motion in 1d...
question mark

an elevator car whose floor to ceiling distance is equal to 2.7m starts from rest with a constant acceleration of 1.2 ms-2 . two seconds later , a bolt drops from car's ceiling.the time taken by bolt to hit floor of elevtor is..plz say..

shyam sundar , 13 Years ago
Grade 11
anser 2 Answers
abhishek upadhyay

Last Activity: 13 Years ago

mention whether elevator is going up or down

this problem will be easier if u solve it in frame of elevator

when bolt gets detached its initial  velocity w.r.t. elevator is 0

abE = ab(g) - aE(g)

       =g - a               if elevator is going down taking down +ve

      or    g+a                "   "      "      "        "  up     "        "      "

 now   2.7 = ubE t   +   abEt2/2

             = 0  +   abEt2/2 

   imp - block moves 2.7 w.r.t elevator

Atharva Baste

Last Activity: 8 Years ago

V0=0
T=?
S=2.7m
A=g+a(lift)=9.8+1.2=11m/s
Using,
s=Vo(t)+(0.5)(A)(T)(T)
=> 2.7/(.5) = 0 (t) + (11)(T)(T)
=>T=.70 sec

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments