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Q. A body starts with an initial vel. of 10 m/s and moves along a st. line with a constant acceleration. When the vel. of the particle is 50 m/s, acc. is reversed in direction. Find vel. of particle when it reaches the starting point.
from SYMMETRY it is clear that the velocity at the starting point is 10 m/s in the opposite direction.
let its accln = a & after time t its velocity is 50 and accln is reversed
Ui = 10m/s, Uf = 50m/s
50 = 10 + at
or at=40 ........................(i)
now its velocity reduces to 0
0=50 - aT ( accln is reversed)
or aT=50 .........................(ii)
when it reaches to initial point
then for reverse motion
v` = 0+ a(t+T)
= 90m/s
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